Your best answer the question. Please newer asked
the stems that you were not able to answer correctly and find the night
go through this module
1. It is a polynomial equation of degree two that can be write in the fom
ax+bx+c=0, where a, b, and care real numbers and a
a Linear Equation
c. Quadratic Equation
b Linear Inequality
d. Quadratic inequality
2. Which of the following is a quadratic equation?
a. 38+8 -4
c. 2x-1-5
b. m-Bm-1=0
d. Sy + 4y 21
3. In the quadratic equation 2x - ex- 5 = 0, which is the quadratem
b.
0.-
d. -
4. In the quadratic equation 2x2 - ex-5= 0, which is the near term?
b. x2
0-9x
a. 2x
a. 2x
5. In the quadratic equation 2x8-9x-5= 0, which is the constante

f(x) is the value of the function. b is the value of the function when x equals zero or the y-coordinate of the point where the line crosses the y-axis in the coordinate plane.

step-by-step explanation:

hope this !

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?