You may have polarized sunglasses that eliminate glare by polarizing the light. When light is polarized, all of the waves are traveling in parallel planes. Suppose vertically polarized light with intensity Io strikes a polarized filter with its axis at an angle of θ with the vertical. The intensity of the transmitted light It and θ are related by the equation Cosθ= √ Io/It. If θ, write It as a function of Io,

Step-by-step explanation:

Given the intensity of the transmitted light It and θ are related by the equation Cosθ= √ Io/It, we are to write lt as a function of lo

Given the equation

Cosθ= √ Io/It

Let us make lt the subject of the formula;

square both sides of the equation

(Cosθ)²= (√ Io/It)²

cos²θ = lo/lt

cross multiply

ltcos²θ = lo

divide both sides by cos²θ

ltcos²θ/ cos²θ= lo/cos²θ

lt = lo/cos²θ

Hence the expression of lt as a function of lo is lt = lo/cos²θ

the answer is y < -3 or   y > 3

-3y > 7 + 2

-3 y > 9

y < -3