Mathematics, 13.10.2020 14:01 LaDariusL33

Solve 3 ax + 4ax = 5ax + 4 for x. Assume a ≠0. A. x = 3 a
B. x=2/a
C. x = 2a
D. x = 1/3a

Answers: 2

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Solve 3 ax + 4ax = 5ax + 4 for x. Assume a ≠0. A. x = 3 a
B. x=2/a
C. x = 2a
D. x...

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More questions: Mathematics Another questions

Solve 3 ax + 4ax = 5ax + 4 for x. Assume a ≠0. A. x = 3 a B. x=2/a C. x = 2a D. x = 1/3a

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Another question on Mathematics

Solve 3 ax + 4ax = 5ax + 4 for x. Assume a ≠0. A. x = 3 a
B. x=2/a
C. x = 2a
D. x = 1/3a