Please assist me with the domain and range of graphs

 see below

Step-by-step explanation:

Domain represents the x-values from the smallest (furthest left) to the biggest (furthest right).

Range represents the y-values from the lowest (furthest down) to the highest (furthest up).

Interval notation: If a value is included (closed dot), use a bracket [  ]

                      If a value is NOT included (open dot), use a parenthesis (  )

                     Note that ± ∞ is never included.

1. Domain: smallest x-value is -4 (included). biggest x-value is 3 (included)

  Range: lowest y-value is 2 (included). highest y-value is 5 (included)

                 D: x = [-4, 3]        R: y = [2, 5]

2. Domain: smallest x-value is -∞ (←). biggest x-value is 2 (included)

  Range: lowest y-value is 2 (included). highest y-value is ∞ (↑)

                 D: x = (-∞, 2]        R: y = [2, ∞)

3. Domain: smallest x-value is -∞ (←). biggest x-value is ∞ (→)

  Range: lowest y-value is -∞ (↓). highest y-value is ∞ (↑)

                 D: x = (-∞, ∞)        R: y = (-∞, ∞)

4. Domain: smallest x-value is -∞ (←). biggest x-value is ∞ (→)

  Range: lowest y-value is -∞ (↓). highest y-value is 4 (included)

                 D: x = (-∞, ∞)        R: y = (-∞, 4]

5. Domain: smallest x-value is -∞ (←). biggest x-value is ∞ (→)

  Range: lowest y-value is 3 (included). highest y-value is ∞ (↑)

                 D: x = (-∞, ∞)        R: y = [3, ∞)

6. Domain: smallest x-value is -2 (included). biggest x-value is ∞ (→)

  Range: lowest y-value is -3 (included). highest y-value is ∞ (↑)

                 D: x = [-2, ∞)        R: y = [-3, ∞)

the statemwnt is the company makes small and large snow cone cups.

large=it holds more then the small

small=it holds less then the large

solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean =

also, median= , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean =  

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.