Mathematics, 25.08.2019 17:10 Tuxkie
Three terms of an arithmetic sequence are shown. f(1)=3, f(3)=6, f(7)=12 what recursive formula could define the sequence ? a. f(n+1)=2f(n) b. f(n+1)=f(n)+3 c. f(n+1)=f(n)+1.5 d. f(n+1)=0.5f(n)
Answers: 1
![an\ arithmetic\ sequence:\\\\ d\ \ \rightarrow\ \ the\ difference\\\\f(n)=f(1)+(n-1)\cdot d\\\\f(n+1)=f(1)+n\cdot d\\\\f(n+1)-f(n)=f(1)+n\cdot d-[f(1)+n\cdot d- d]=\\\\=f(1)+nd-f(1) -nd+d=d\\\\\Rightarrow\ \ \ f(n+1)=f(n)+d](/tpl/images/0196/9522/4ffae.png)
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Three terms of an arithmetic sequence are shown. f(1)=3, f(3)=6, f(7)=12 what recursive formula coul...
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