PLEASE HELP!! If f (x) = 4x^-2 + 1/4x^2 + 4, then f’(2) =

Finding the derivative, we have that f'(2) = 0, option D.

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The function is:

The derivatives are:

Thus, the derivative of the function is:

At x = 2:

Thus f'(2) = 0, option D.

A similar problem is given at link

Work Shown:

f(x) = 4x^(-2) + (1/4)x^2 + 4

f ' (x) = 4*(-2)x^(-3) + (1/4)*2x power rule

f ' (x) = -8x^(-3) + (1/2)x

f ' (2) = -8(2)^(-3) + (1/2)*(2)

f ' (2) = 0

y=-2.5x+12.5

step-by-step explanation:

5y=2x+10

y=0.4x+2

slope=-2.5

5=-2.5*3+b

b=12.5

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