WILL MARK BRAINLIEST, PLEASE EXPLAIN HOW YOU GOT YOUR ANSWER!!! The equation for lines can be written as y = –6x + 2. Line t includes the point (–6, –7) and is perpendicular to line s. What is the equation of line t?

y=1/6x-6

Explanation:
What we know:
- Equation for line S: y=-6x+2
- Line T is perpendicular to line S
- Line T passes through the point (-6,-7)

To find the answer, we would need to understand two things, the first being what exactly is going on with the equation: y=-6x+2.

It’s organized in slope-intercept form, which is y=mx+b. Here’s what the variables mean:

Y=the y variable
M=the slope
X=the x variable
B=the y-intercept (the point on the line that crosses the y axis)

Knowing this, we can look at the equation for line S again: y=-6x+2. -6 is the slope of line S and 2 is the y-intercept of line S.

The second thing we need to understand is that the slope of a second line that is perpendicular to the first line is equal to the NEGATIVE RECIPROCAL of the slope of the first line.

Reciprocal: the “flip” of a fraction where the denominator and the numerator switch places

So, for example, let’s say the slope of line A=6. The slope of the line perpendicular to line A would be -1/6.

Let’s try another example: the slope of line B=-4/5. The slope of the line perpendicular to line B would be 5/4 (because two negatives makes a positive)

And here, for your question, the slope of line S=-6. Therefore, the slope of line T would be 1/6.

Awesome! We found the slope, which means so far, the equation of line T looks like this:

y=1/6x+b

All we need now is the y-intercept, which is “b” in the equation y=mx+b.

To do this, we plug in the point that the question provided us, (-6,-7), and solve. We would plug in -7 as the y variable and -6 as the x variable.

y=1/6x+b
-7=1/6(-6)+b
1) multiply 1/6 and -6
-7=-1+b
2) add 1 to both sides of the equation to isolate b
-6=b

Aha! There we have it, -6 is the y-intercept of line T.

Now, we have completed our equation:

y=1/6x-6

I hope this helps! Please comment if you have any questions.