An insurance company regularly reviews official police reports of traffic accidents in a particular region of the country so that it can price its premiums in that region appropriately. A review of a random sample of 582 accident reports showed that in 91 accidents, a teenage driver was found to be at fault. Required:
Report the upper bound of a 90% confidence interval for the true proportion of accidents in the area that are caused by teenagers, to three decimal places.

Answer and Step-by-step explanation:

Random sample = 582

No. of accidents = 91

P = 91 / 582 = 0.156

Confidence interval for proportion of accidents:

P ± z √(p(1-p)/n)

Where,

n = 582

p = 0.156

z = 1.645

Formula:

P ± z √(p(1-p)/n)

put these values in formula, we get:

 = 0.156 ± 1.645 √(0.156(1-0.156)/582)

 = 0.156 ± 1.645 √(0.1316/582)

= 0.156 ± 1.645 (0.01483)

= 0.156 ± 0.0244

= (0.1804, 0.1316)

idk

step-by-step explanation:

he spend 5.1 minutes chatting with his friends.

step-by-step explanation:

2/5+1/2=9/10

6/1-9/10=5.1