How can a regular hexagon be folded to show that it has reflectional symmetry? fold the hexagon along a line from a vertex to the midpoint of an opposite side. fold the hexagon along a line connecting the two midpoints of adjacent sides. fold the hexagon along a line that bisects two vertex angles. fold the hexagon along a line that creates a right angle at a vertex.

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.