Mathematics, 15.10.2020 23:01 jobrains3220

Maple tree diameters in a forest area are normally distributed with mean 10 inches and standard deviation 2.2 inches. Find the proportion of trees having a diameter less than 9 inches.

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Answer from: Hakika

The proportion of trees having a diameter less than 9 inches is 32.64%

z score is used to determine by how many standard deviations the raw score is above or below the mean.

It is given by:

$z=\frac{x-\mu}{\sigma} \\\\where\ x\ is\ raw\ score.\mu\ is\ mean,\sigma\ is \ standard \ deviation$

Given that μ = 10, σ = 2.2, hence:

$For\ x$

From the normal distribution table, P(x < 9) = P(z < -0.45) = 0.3264 = 32.64%

The proportion of trees having a diameter less than 9 inches is 32.64%

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Answer from: jerry7792

0.32472

Step-by-step explanation:

Maple tree diameters in a forest area are normally distributed with mean 10 inches and standard deviation 2.2 inches. Find the proportion of trees having a diameter less than 9 inches.

The formula for calculating a z-score is z = (x-μ)/σ

where x is the raw score

μ is the population mean

σ is the population standard deviation

z = (9 - 10)/2.2

z = -1/2.2

= -0.45455

Probability value from Z-Table:

P(x ≤ 9) = P(x < 9)

= 0.32472

Therefore, the proportion of trees having a diameter less than 9 inches is

0.32472

Answer from: Quest

10 you would take 50/ .2

step-by-step explanation:

Answer from: Quest

answer:

total cost for tiles and paints is $924.

step-by-step explanation:

we have been given that a community hall is in the shape of a cuboid. the hall is 40m long 15m high and 3m wide.

the paint will be required for 4 walls and ceiling.

let us find area of walls and ceiling.

$\text{area of walls and ceiling}=(2*40*15)+(2*3*15)+(40*3)$

$\text{area of walls and ceiling}=1200+90+120$

$\text{area of walls and ceiling}=1410$

therefore, the area of walls and ceiling is 1410 square meters.

given: cost for 10 litre of paint is $10 and 10 litre paint covers 25 square meter. therefore,

$\text{ the total painting cost}=10*(\frac{1410}{25})$

$\text{ the total painting cost}=10*56.4=564$

therefore, the total painting cost is $564.

tiles will be required for floor. let us find the area of floor.

$\text{area of floor} = 40*3\text{ square meters}$

$\text{area of floor} =120\text{ square meters}$

given: 1m squared floor tiles costs $3. so,

$\text{total cost for tiles} = 3*120 = 360$

therefore, the total tiles cost is $360.

now let us find combined total cost of tiles and paint.

$\text{combined total cost}= 564+360 = 924$

therefore, the combined total cost of tiles and paint is $924.

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