What is 50 divided by 4260 long diving

85 remainder of 1

Step-by-step explanation:

step 1: Start by setting it up with the divisor 5 on the left side and the dividend 426 on the right side

Step 2: The divisor (5) goes into the first digit of the dividend (4), 0 time(s). Therefore, put 0 on top

Step 3: Multiply the divisor by the result in the previous step (5 x 0 = 0) and write that answer below the dividend.

Step 4: Subtract the result in the previous step from the first digit of the dividend (4 - 0 = 4) and write the answer below. Then Move down the 2nd digit of the dividend (2)

Step 5: The divisor (5) goes into the bottom number (42), 8 time(s). Therefore, put 8 on top, Multiply the divisor by the result in the previous step (5 x 8 = 40) and write that answer at the bottom

Step 6: Subtract the result in the previous step from the number written above it. (42 - 40 = 2) and write the answer at the bottom. Then Move down the last digit of the dividend (6)

Step 7: The divisor (5) goes into the bottom number (26), 5 time(s). Therefore put 5 on top .Multiply the divisor by the result in the previous step (5 x 5 = 25) and write the answer at the bottom

Step 8: Subtract the result in the previous step from the number written above it. (26 - 25 = 1) and write the answer at the bottom.

5/426

Step-by-step explanation:

45

step-by-step explanation:

when functions are first introduced, you will probably have some simplistic "functions" and relations to deal with, usually being just sets of points. these won't be terribly useful or interesting functions and relations, but your text wants you to get the idea of what the domain and range of a function are. small sets of points are generally the simplest sorts of relations, so your book starts with those.

step-by-step explanation:

state the domain and range of the following relation. is the relation a function?

{(2, –3), (4, 6), (3, –1), (6, 6), (2, 3)}

the above list of points, being a relationship between certain x's and certain y's, is a relation. the domain is all the x-values, and the range is all the y-values. to give the domain and the range, i just list the values without duplication:

domain: {2, 3, 4, 6}

range: {–3, –1, 3, 6}

(it is customary to list these values in numerical order, but it is not required. sets are called "unordered lists", so you can list the numbers in any order you feel like. just don't duplicate: technically, repetitions are okay in sets, but most instructors would count off for this.)

while the given set does indeed represent a relation (because x's and y's are being related to each other), the set they gave me contains two points with the same x-value: (2, –3) and (2, 3). since x = 2 gives me two possible destinations (that is, two possible y-values), then this relation is not a function.

note that all i had to do to check whether the relation was a function was to look for duplicate x-values. if you find any duplicate x-values, then the different y-values mean that you do not have a function. remember: for a relation to be a function, each x-value has to go to one, and only one, y-value.

state the domain and range of the following relation. is the relation a function?

{(–3, 5), (–2, 5), (–1, 5), (0, 5), (1, 5), (2, 5)}

i'll just list the x-values for the domain and the y-values for the range: