Mathematics, 16.10.2020 06:01 precioushayhay

It is given that ABCD is a parallelogram, so AB¯¯¯¯¯∥DC¯¯¯¯¯ by the definition of parallelogram. So, ∠1≅ ∠2 by the alternate interior angles theorem. It is also given that DC¯¯¯¯¯ bisects ∠BDE , so ∠2≅ by the Therefore, ≅∠3 by the

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It is given that ABCD is a parallelogram, so AB¯¯¯¯¯∥DC¯¯¯¯¯ by the definition of parallelogram. So,...

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It is given that ABCD is a parallelogram, so AB¯¯¯¯¯∥DC¯¯¯¯¯ by the definition of parallelogram. So, ∠1≅ ∠2 by the alternate interior angles theorem. It is also given that DC¯¯¯¯¯ bisects ∠BDE , so ∠2≅ __ by the __ Therefore, __ ≅∠3 by the __

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It is given that ABCD is a parallelogram, so AB¯¯¯¯¯∥DC¯¯¯¯¯ by the definition of parallelogram. So, ∠1≅ ∠2 by the alternate interior angles theorem. It is also given that DC¯¯¯¯¯ bisects ∠BDE , so ∠2≅ by the Therefore, ≅∠3 by the