Line JK passes through points J(–4, –5) and K(–6, 3). If the equation of the line is written in slope-intercept form, y = mx + b, what is the value of b? –21
–4
11
27

Find the slope that passes between the points.

(y₂ - y₁) / (x₂ - x₁)

J(-4, -5)

K(-6, 3)

(3 - (-5)) / (-6 - (-4))

(3 + 5) / (-6 + 4)

8 / -2

-4

Now slap that slope into the formula and substitute on of the coordinates to the formula to solve for b (I'll take point K's coordinate):

y = mx + b

y = -4x + b

3 = -4(-6) + b

3 = 24 + b

3 - 24 = b

- 21 = b

b = -21

7. d. 64

8. i. 32

9. c. 125

10. j. none of the above

11. d. 81

12. i. 216

13. e. none of the above

14. g. 240

15. e. none of the above

16. g. 32

17.   e. none of the above