Triangle ABC is located in the third quadrant of a coordinate plane. If triangle ABC is reflected across the −axis to obtain triangle, A’B’C’, which statement is true? A. Triangle A’B’C’ lies in quadrant II and is congruent to Triangle ABC B. Triangle A’B’C’ lies in quadrant IV and is congruent to Triangle ABC C. Triangle A’B’C’ lies in quadrant II and is not congruent to Triangle ABC D. Triangle A’B’C’ lies in quadrant IV and is not congruent to Triangle ABC

The answer is B

Step-by-step explanation:

It’s Triangle A’B’C’ lies in quadrant II and is congruent to Triangle ABC

Step-by-step explanation:

I just took the test

the direct variation says that:

then the equation is of the form is given by:

            where k is the constant variation.

from the given table:

consider any value of x and m(x)=y

x = 2 and m(x)=y = 3

substitute these value in [1]; we have;

divide both sides by 2 we get;

⇒

check:

put x = -1 and m(x) = -1.5

substitute in the equation:

-1.5 = -1.5                   true

therefore, the function m(x) represents a direct variation

graph of this function as shown below:

idk

step-by-step explanation:

use that smart brain