Peter attempted to use the divide-center method to find the line of best fit on a scatterplot. What was his mistake?

He had a different number of points to the left of the vertical line than to the right of the vertical line.

He had a different number of points above the line of best fit than below the line of best fit.

a: He had a different number of points to the left of the vertical line than to the right of the vertical line.

Step-by-step explanation:

edg2021

109 is the nearest whole number/final answer! : )

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine