The sum of three consecutive odd integers is 57. what are the three integers

17,19,21

Step-by-step explanation:

let the first odd number be "x"

formular : (x)+(x+2)+(x+4).

3x+6=57

3x=57-6

3x=51

x=51/3

x=17

apply the formular.

17,(17+2),(17+4)

17,19,21.

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option