A school principal plans to form teams from 126 third-graders, 180 fourth-graders, and 198 fifth-graders so that there is the same number of students from each grade level on each team. If all students participate, what is the largest possible number of teams and how many students will there be on each team?

There are 9 teams possible each having 14 third-graders, 20 Fourth-graders, 22 Fifth-graders

Step-by-step explanation:

126 third-graders

180 fourth-graders

198 fifth-graders

Find the highest common factor of 126, 180, 198

Factors of 126: 1, 2, 3, 6, 7, 9, 14, 18, 21, 42, 63, 126.

Factors of 180 : 1, 2, 3, 4, 5, 6, 9, 10, 12, 15, 18, 20, 30, 36, 45, 60, 90, 180

Factors of 198: 1, 2, 3, 6, 9, 11, 18, 22, 33, 66, 99, 198.

The highest common factor of 126, 180, 198 is 9

The largest possible number of teams that can be formed is 9

Each team has

third-graders = 126 / 9

= 14

Fourth-graders = 180 / 9

= 20

Fifth-graders = 198 divided by 9

= 22

There are 9 teams possible each having 14 third-graders, 20 Fourth-graders, 22 Fifth-graders

2. angles qrt and qst both measures 156 degrees.

step-by-step explanation:  

we have been given a diagram of a circle and we are told that measure of arc qvt is 156 degrees.  

we can see from our given diagram that angle qrt and angle qst subtends to arc qvt.

since we know that angles subtended by the same arc at the circumference are always equal.

by angle subtended by same arc theorem, measure of angle qrt and angle qst will be equal to the measure of arc qvt.

therefore, angles qrt and qst both measures 156 degrees and 2nd statement is the correct choice.

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;