Look at the two equations: 3x + 6 = 21
3x + 6 < 21
Which statement best describes the process used to solve the equations?
In both cases, subtract 6 from both sides, but reverse the inequality sign when doing that for the inequality.
In both cases, divide by –3 on both sides, but reverse the inequality sign when doing that for the inequality.
The process is exactly the same for solving the equation and solving the inequality.
The process for solving the equation is entirely different from solving the inequality.

i think its In both cases, subtract 6 from both sides, but reverse the inequality sign when doing that for the inequality.

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

the answer is mp

step-by-step explanation: