A gold mine has two elevators one for equipment and another for miners. The elevator for the miners descends 13 feet per second. The elevator for the miners descends 13 feet per second. One day the equipment elevator begins to descend. After 18 seconds the elevator for the miners begins to descend. What is the position of each elevator relative to the surface after another 19 seconds? At that time, which elevator is deeper?

The equipment elevator is positioned 481 feet closer and the miner equipment is positioned 342 feet closer relative to the surface. The equipment elevator is deeper.

Step-by-step explanation:

The rate that both elevators descend are the same according to the information given in the question.

After 18 seconds, the equipment elevator has descended 18 x 13 = 234 feet.

After another 19 seconds, the equipment elevator has descended for a total of 37 seconds which results in 481 feet and the miner elevator has descended for 19 seconds which gives us a descend of 342 feet.

So they are 481 and 342 feet closer relative to the surface and the equipment elevator is deeper since it has descended for a longer period of time.

I hope this answer helps.

i = 2 / - 5

step-by-step explanation:

evaluation of ( 2 - 4 ) ( p + q ) when p = 2 and q = 5 i, by putting values of p and q,                                                                    

77

step-by-step explanation: