Scientists examined data on mean summer sea‑surface temperatures (in degrees Celsius) and mean coral growth (in millimeters per year) over a several‑year period at locations in the Red Sea. Temperature (∘C) 29.55 29.96 30.04 30.28 30.34 30.47 30.81
Growth (mm/y) 2.64 2.37 2 .74 2.52 2.34 2.46 2.31

Required:
Use your calculator to find the mean and standard deviation of both sea surface temperature x and growth y and the correlation r between x and y . Then use these basic measures to find the slope and intercept of the least‑squares line for predicting y from x .

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Step-by-step explanation:

Given the data:

Temperature (∘C) 29.55 29.96 30.04 30.28 30.34 30.47 30.81

Growth (mm/y) 2.64 2.37 2.74 2.52 2.34 2.46 2.31

Using calculator and treating temperature and growth data as samples :

Temperature :

Mean : ΣX/n

n = sample size

Mean temperature (m) = 211.45 / 7

Mean temperature = 30.21°C

Standard deviation (s) :

Sqrt(Σ(X - m)²/n - 1)

s = 0.403

Growth:

Mean : ΣX/n

n = sample size

Mean growth (m) = 17.38 / 7

Mean growth = 2.483 mm/yr

Standard deviation (s) :

Sqrt(Σ(X - m)²/n - 1)

s = 0.161

Using the correlation Coefficient a calculator : the correlation Coefficient is - 0.6278, This shows that a negative relationship exists between both variables.

The intercept of the graph = 17.812

The slope of the relationship : -0.504

sites:

sas (side angle side)

aa (angle angle)

sss(side side side)

sas find two sides with an angle in between

aa is finding two angles and the third will add up to 180

sss find all sides

step-by-step explanation: