Which number supports the given conjecture?
if a number is divisible by both 2 and 3, then the number is also divisible by 6.
a.
16
b.
23
c.
27
d.
36

A. 16 is divisible by 2 but not divisible by 3
B. 23 is not divisible neither by 2 nor 3
C. 27 is not divisible by 2, however it's divisible by 3
D. 36 is divisible both by 2 and 3

So the only number we can focus on is 36:

36 ÷ 2 = 18
36 ÷ 3 = 12
36 ÷ 6 = 6

D, 36 supports the given conjecture.