The lengths of salamanders have a normal distribution with mean 15cm, and standard deviation 2cm. What is the probability a salamander has length between 12.2cm and 16.5cm

The probability a salamander has a length between 12.2cm and 16.5cm is 0.6930

Step-by-step explanation:

We start by finding the z-score of each

Mathematically;

z-score = (x - mean)/SD

for 12.2 cm

z-score = (12.2 - 15)/2 = -2.8/2 = -1.4

For 16.5 cm

z-score = (16.5 -15)/2 = 1.5/2 = 0.75

So the probability we want to calculate is;

P( -1.4 < z < 0.75)

we can calculate this using the normal distribution table

Mathematically;

P( -1.4 < z < 0.75) = P( z < 0.75) - P( z < -1.4)

= 0.2263 + 0.30738

= 0.69262

the answer is (-8,-5)

step-by-step explanation:

the endpoint to midpoint is half the length. the length is (-2,-1) so when you are at the midpoint just add it to it to find your answer -6+(-2)= -8 and -4+(-1)=-5 so (-8,-5)