Use the work shown below to write the equation for a line that has a slope of Negative two-fifths and passes through (15, –2). y = mx + b 1. Substitute the known values: negative 2 = negative two-fifths (15) + b. 2. Solve for b: negative 2 = negative 6 + b. b = 4. What is the equation of the line in slope-intercept form? Negative 2 = negative two-fifths x + 4 y = negative two-fifths (15) + 4 y = negative two-fifths x minus 4 y = negative two-fifths x + 4

Step-by-step explanation:

The formula:

The steps:

The result

What is the equation of the line in slope-intercept form?

the answer is d

Step-by-step explanation:

just did it on edg

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)