the sum of three numbers is 55. the second number is twice the first and the third number is five less than the second. What are the three numbers?

Let the first number be = x

Then the second number = 2x

The third number = 2x - 5

Their sum = 55

This can be written in an equation as =

x + 2x + 2x - 5 = 55

= x + 2x + 2x = 55 + 5 ( transposing -5 from LHS to RHS changes -5 to +5 )

= x + 2x + 2x = 60

= 5x = 60

= x = 60 ÷ 5 ( transposing ×5 from LHS to RHS changes ×5 to ÷5 )

= x = 12

The first number = x = 12

The second number = 2x = 2 × 20 = 24

The third number = 2x - 5 = 24 - 5 = 19

Therefore , the three numbers are 12 , 24 and 19 .

22

step-by-step explanation:

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.