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Mathematics, 17.10.2020 08:01 lesheaux

1.) (14 x^3 y^2 z^5)^7 = 2.) (27 + 15)^3 =42^7

3.) (4/x)^11 =

4.) (x^2y^-7z^11)^0 =

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1.) (14 x^3 y^2 z^5)^7 = 2.) (27 + 15)^3 =42^7

3.) (4/x)^11 =

4.) (x^2y^-7...
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