If LCM of two prime numbers a and b (a>b) is 783 , then the value of 2ab-3a is?

LCM(a, b) means the least common multiple between a and b.

LCM(a,b) = a*b/GCF(a,b)

Where GCF(a,b) =  greatest common factor between a and b.

Then the smallest common multiple between two prime numbers is the product between those prime numbers (Because the only common factor between prime numbers is 1).

LCM(a,b) = a*b = 783.

Now, to find the values of a and b, we can divide 783 by different primes, and see when the quotient is an integer:

(I ignore the number 2 because 783 is not even, so i will start with the prime 3)

783/3 = 261

Then the two primes are 3 and 261

We also know that a > b

Then:

a = 261

b = 3.

2*a*b - 3*a = 2*261*3 - 3*261 = 261*3*(2 - 1) = 261*3 = 783

not enough information

step-by-step explanation:

we cannot know this, because the other students could have handed out 10 flyers, or they could have handed out 100. one way, the mean would go up, and another way, the mean would go down.