The members of the Math team contributed a total of $9.10 for the party after their practice. Each member contributed the same amount of money in dimes only. How many members are in the team and how much money did everyone contribute? Give all possible answers.

Number of possibilities

1) 91 members that contribute 1 dime each ($0.10)

2) 13 members that contribute 7 dimes each ($0.10 × 7 = $0.70)

3) 70 members that contribute 13 dimes each ($0.10 × 13 = $0.13)

Step-by-step explanation:

A dime = $0.10 in dollars

We are told that:

The total amount contributed = $9.10 for the party after their practice.

Each member contributed the same amount of money in dimes only.

Let the number of members be represented as: x

Number of possibilities

We find the factors of $9.1

= 1, 0.7, 0.13, 9.1

= 1 × 9.1

= 0.7 × 13

= 0.13 × 70

Hence:

1) $0.10 × x = $9.10

x = $9.10/$0.10

x = 91

Therefore, from the calculation above, there are 91 members and each of them contributed the same amount which was 1 dime ($0.10).

2)

7($0.10 )× x = $9.10

x = $9.10/$0.70

x = 13

Therefore, from the calculation above, there are 13 members that contribute 7 dimes each ($0.10 × 7 = $0.70)

3) 13($0.10) × x = $9.10

x = $9.10/$0.13

x = 70

Therefore, from the calculation above, there are 70 members that contribute 13 dimes each ($0.10 × 13 = $0.13)

answer: i believe c. is the answer sorry if i am wrong

step-by-step explanation:

for the first question it would be the second answer for the second question it would be the third answer and for the third question it would be the first answer

step-by-step explanation: