A bowling ball is dropped from a height of 35 feet. Write a function that gives the height h (in feet) of the bowling ball after t seconds.

h(t) = 16t² + 35

Step-by-step explanation:

Given:

Height (h) = 35 feet

Acceleration (a) = 32 ft/sec (approx)

Find:

Equation for height in time

Computation:

h(t) = -(1/2)at² + ut + h

h(t) = -(1/2)(32)t² + (0)(t) + 35

h(t) = -16t² + 35

b i think

step-by-step explanation:

not really sure

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204