At a birthday party, 5 boys and 3 girls are seated in a row. How many different arrangements are possible if: the leftmost and rightmost end seats are occupied by boys, and no girls are seated next to each other?
(no explanation needed)

1: -2 3/4, -2 1/2, -14, 0, 3, 8 1/3

2: -4, -3, -2 1/2, -2 1/4, 3 1/4,

step-by-step explanation:

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

175

step-by-step explanation:

2 inches x 10 miles = 200 miles - 3 inches = 175

so, converting firstly the mixed fractions to improper fractions and then "adding".