Fully simplify.
(-2V-49)(5V-100)

(-2v-49)x(5v-100)

Multiply each term in the first parentheses by each term in the second parentheses (foil)

-2vx5v-2vx(-100)-49x5v-49 x (-100)

calculate the product

-10v²-2v x(-100)-49x5v-49 x(-100)

-2vx5v

Multiply the numbers

-10v x v

the same of the other one ok is different how i am doing

-2vx5v

If a term doesn't have an exponent , it is considered that the exponent is 1

-10v^ 1 x v

-10v^1 xv^1

Multiply the terms with the same base by adding their exponents

-10v^1 x v^1

-10v^1+1

to add the numbers using a number line, start from zero

1+1=2

Since 1 is positive, move the point 1 unit to the right

The result is 2

-10v^2

That's it . Hope it wasn't too hard to understand?

PLEASE MARK ME AS BRAINLIEST

where r the answers

step-by-step explanation: