Can someone help me with this
2x+4y+3z=6
x-2y+z=-5
-x-3y-2z=-7
solve for x, y,z

x = -7 2/3, y = 1 1/3 and z = 5 1/3.

Step-by-step explanation:

2x+4y+3z=6      1

x-2y+z=-5         2

-x-3y-2z=-7      3

Add equations 2 and 3 to eliminate x:

-5y - z = -12   4

Multiply equation 2 by - 2:

-2x + 4y  - 2z = 10

Add this to equation 1:

8y + z = 16   5

Now add equation 4 to equation 5:

3y = 4

y = 4/3 = 1 1/3.

Now find z by substituting for y in equation 4:

-5(4/3) - z = -12

z = 12 - 20/3

z = 36/3 - 20/3 = 16/3 = 5 1/3.

Finally, we find x by substituting for y and z in equation 1:

2x + 4*4/3 + 3*16/3 = 6

2x = 6 - 16/3 - 16

2x =  18/3 - 16/3 - 48/3 = -46/3

x = 23/3 =  7 2/3.

answer: i'm great at algebra

~coco

step-by-step explanation:

false

step-by-step explanation:

false.   two legs of the trapezoid would be congruent, but the other two would not.   were all the legs congruent, then we'd have a square; were the 2 shorter sides congruent and the 2 longer sides also congruent, we'd have a rectangle.