For what value of a does (1/7)^3a+3=343^a-1?

ok, remember that when

x^a=x^b, when x=x, then a=b

also

x^-m=1/(x^m)

and

(x^m)^n=x^(mn)

so

we can rewrite 1/7 as 7^-1

so

and 343=7^3

7=7 so

-3a-3=3a-3

add 3a to both sides

-3=6a-3

add 3 to both sides

0=6a

0=a

a=0

0

By: apologiabiology

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