Find three consecutive even integers such that their sum decreased by 34 is equal to the first integer. Find the first integer.

The first number: 14

The second number: 16

The third number: 18

Step-by-step explanation:

Equations

Let's assume:

x=the first even number.

x+2=the second even number

x+4=the third even number

The sum of all three is: x + x + 2 + x + 4

The condition states the sum decreased by 34 equals the first number:

x + x + 2 + x + 4 - 34 = x

Moving all the variables to the left side and the numbers to the right side:

x + x + 2 + x + 4 - 34 - x = 34 - 2 - 4

Simplifying:

2x =  28

Solving:

x = 28 / 2 = 14

The first number: 14

The second number: 16

The third number: 18

answer: idk

step-by-step explanation:

wth is with the little mtn top and what are you talking about like fix your words and accually make sence with them and i like was in a completly different question like three times like it seems like your ilitteret