Let $f(x) = 2x - 3$ and $g(x) = x + 1$. What is the value of $f(1 + g(2))$?

The value of f(1 + g(2)) is 5

Step-by-step explanation:

Let us solve the question

∵ f(x) = 2x - 3

∵ g(x) = x + 1

We need to find the value of f(1 + g(2))

That means we will replace x in f(x) by 1 + g(2)

→ g(2) means substitute x in g by 2

∵ g(x) = x + 1

∵ x = 2

∴ g(2) = 2 + 1

∴ g(2) = 3

∵ x of f = 1 + g(2)

∵ g(2) = 3

∴ x of f = 1 + 3

∵ x of f = 4

→ To find f(1 + g(2)) substitute 1 + g(2) by 4

∵ f(x) = 2x - 3

∵ x = 4

∴ f(4) = 2(4) - 3

∴ f(4) = 8 - 3

∴ f(4) = 5

∴ f(1 + g(2)) = 5

hello :

70y^8 + 30y^6 = 2 ( 35 y^8 + 15y^6)

the lenght is : 35 y^8

the width is : 15y^6

circle area = pi * radius^2

if diameter = 10 then radius = 5

circle area = pi * 5^2

circle area = pi * 25

circle area = 78.5398163397 square units

step-by-step explanation: