Please help will give brainliest.

x<9 and x>1/13

1/13<x<9

Step-by-step explanation:

First, let's find the value of x in the first equation:

6((x-1)/2-(x-3)/3)<2*6

(3x-3)-(2x-6)<12

3x-3-2x+6<12

x+3<12

x<9

Now, let's find the value of x in the second equation:

13x-1>0

13x>1

x>1/13

Since x has to satisfy both of these, the answer would be x<9 and x>1/13; in other words, 1/13<x<9.

each side has a different length.  

step-by-step explanation:

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.