1.2.71 Question Hel
How many gallons of a 60% antifreeze solution must be mixed with 80 gallons of 30% antifreeze to get a mixture that is 50% antifreeze?
The number of gallons that must be mixed is (gallons,
(Round to the nearest whole number.)
(11)
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Step-by-step explanation:

Set up an equation, where x is the number of gallons of 60% antifreeze solution.

Represent the percentages of antifreeze with decimal values.

0.6x + 0.3(80) = 0.5(x + 80)

Simplify and solve for x:

0.6x + 24 = 0.5x + 40

0.1x = 16

x = 160

So, you have to mix 160 gallons of a 60% antifreeze solution

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !

exactly you go it

step-by-step explanation: