Show all work to identify the asymptotes and zero of the function f(x)=5x (over) x^2-25

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Step-by-step explanation:

The function will have a zero where the numerator is zero:

  5x = 0

  x = 0 . . . . divide by 5

The zero of the function is x=0.

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The function will have vertical asymptotes where the denominator is zero:

  x^2 -25 = 0

  x^2 = 25 . . . . add 25

  x = ±5 . . . . . . take the square root

The function will have vertical asymptotes at x = -5 and x = 5.

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When x gets large, the magnitude of the function is approximately ...

  5x/x^2 = 5/x

As x approaches infinity, this value approaches zero.

The function will have a horizontal asymptote at y = 0.

its a little blurry tbh

step-by-step explanation:

answer: y = -12x + 108

step-by-step explanation: do (y = m x+b) formula.