LOOK AT THE IMAGE ABOVE AND SOLVE IT FOR TWO DIFFERENT WAYS!! Please help its due today!

Step-by-step explanation:

Ist method - Area of the triangle + Area of the  trapezium

Area of triangle = 1/2 × b × h

here, b = 8 cm but h is not given

so we will find h by pythagoras theorem

AC^2 = AB^2 + BC^2

10^2 = 8^2 + BC^2

100 = 64 + BC^2

BC^2 = 36

BC = √36

BC = 6

∴ h = 6cm

area of triangle = 1/2 × b × h

= 1/2 × 8 × 6

= 24 cm^2

Area of trapezium = 1/2 ( a + b ) h

Here a = 13cm

         b = 25 - 8 = 17 cm

         h = 6 cm

So area = 1/2 ( a + b ) h

= 1/2 ( 13 + 17 ) 6

= 90 cm^2

So total area =  Area of the triangle + Area of the  trapezium

= 24 cm^2 + 90 cm^2 = 114 cm^2

2nd method - Area of the entire figure

Since the figure is a trapezium,

Area of trapezium = 1/2 ( a + b ) h

here, a = 13cm

        b = 25 cm

        h = 6 cm

Area of trapezium = 1/2 ( a + b ) h

= 1/2 ( 13 + 25 ) 6

= 114 cm^2

Hope this helps

plz mark as brainliest

not a very clear diagram sorry luv but i just cant really see the question  <3

step-by-step explanation:

i'm a sophomore in connections, i'd recommend checking on jishka.com they have a large range of questions and answers from our school.