0.0000123 written in standard form is__

1.23 ×

Step-by-step explanation:

A number expressed in standard form has the form

a ×

where 1 ≤ a < 10 and n is an integer

Express the number given as a number between 1 and 10, that ia

1.23 ×

We require to obtain the original number by moving the decimal point by moving the decimal point back 5 places to the left.

Move to the right then n > 0

Move to the left then n < 0

Thus

0.0000123 = 1.23 ×

. + λrh() e 1 1 2 4 4 4 4 4 3 4 4 4 4 4 + th−1(− s(x)2 dx ω + λrh−1() e 2 1 2 4 4

step-by-step explanation:

step-by-step explanation: