“Write an equation and solve for the unknown” I know it’s a lot but can someone help me with this

g) x = 30

h) x = 30

i) m = 55

j) x = 24

k) k = 45

Step-by-step explanation:

G)

all angles of a triangle add up to 180.

the square in the bottom right of the triangle is 90 btw

2x + x + 90 = 180

3x + 90 = 180

3x + 90 - 90 = 180 - 90

3x = 180 - 90

3x = 90

3x/3 = 90/3

x = 30

H)

this is an Isosceles triangle.

that means the bottom two angles are equal.

75 + 75 + x = 180

x + 150 = 180

x + 150 - 150 = 180 - 150

x = 180 - 150

x = 30

I)

2m is supplementary to the bottom right angle of the triangle.

that means they add together to make 180.

80 + 30 + (180 - 2m) = 180

110 - 2m = 180 - 180

110 - 2m = 0

110 = 2m

110/2 = m

55 = m

J)

to save time I'm not going to write out the steps, its the same as the i.

2x + 3x + (180 - 120 ) = 180

5x + 60 = 180

5x = 180 - 60

5x = 120

x = 120/5

x = 24

K)

imagine this as a triangle and a square.

sorry I'm not sure how to explain this -.-

but the equation would be

k + k + 90 = 180

2k + 90 = 180

2k = 180 - 90

2k = 90

k = 45

L)

Im not sure how to solve this, I'm sorry :( hope you figure it out!

perimeter of the first rectangular board is 9 feet.

step-by-step explanation:

let p = perimeter of first board.

l = length of first board

w = width of first board

length of first board = 2 * width of first board - 3

l = 2w - 3

perimeter of first board = 2l + 2w

since l = 2w-3, then

p = 2*(2w-3) + 2w which equals 4w-6 + 2w which equals 6w-6

length and width of the second board are reciprocals of corresponding length and width of the first board.

length of second board = 1/(2w-3)

width of second board = 1/w

perimeter of second board is 1/5th perimeter of the first board.

perimeter of second board = p/5

perimeter of the second board = (2/(2w-3) + 2/w)

since the perimeter of the first board is 5 times the perimeter of the second board, this means that:

6w-6 = 5*(2/(2w-3) + 2/w)

which is the same as:

6w-6 = (10/(2w-3) + 10/w)

if we multiply both sides of this equation by (2w-3), we get:

(6w-6)*(2w-3) = 10 + 10*(2w-3)/w

if we multiply both sides of this equation by w, we get:

(6w-6)*(2w-3)*w = 10*w + 10*(2w-3)

we can simplify this to become:

(6w-6)*(2w-3)*w = 10w + 20w - 30

which becomes:

(6w-6)*(2w-3)*w = 30w-30

if we divide both sides of this equation by (6w-6), we get:

(2w-3)*w = (30w-30)/(6w-6)

which becomes:

(2w-3)*w = 5

this can be simplified to:

2w^2 - 3w = 5

subtract 5 from both sides of this equation to get:

2w^2 - 3w - 5 = 0

which can be factored into:

(2w-5)*(w+1) = 0

which makes:

w = 5/2

or

w = -1.

w can't be negative so the only possible answer is w = 5/2.

if w = 5/2, then

p = 2w-3 = 5-3 = 2

we have:

p = 2

w = 5/2

p = 2l + 2w gets p = 4 + 5 = 9

the perimeter of the first board is 9 feet.

since the perimeter of the second board is 1/5 the perimeter of the first board, the perimeter of the second board is 9/5.

to see if that's correct, we substitute known values for l and w into the second board.

the length of the second board is 1/l.

this becomes 1/2.

the width of the second board is 1/w

this bgecomes 1/(5/2) = (2/5)

let l2 = length of second board.

let w2 = width of second board.

l2 = (1/2)

w2 = (2/5)

let p2= perimeter of second board.

then p2 = 9/5

since p2 = 2*l2 + 2*w2, we should get p2 = 9/5 using the dimensions of l2 and w2.

2 * l2 = 2 * (1/2) = 1

2 * w2 = 2 * (2/5) = 4/5

1 is the same as 5/5

5/5 + 4/5 = 9/5

p2 checks out good.

the dimensions as given are good.

answer to the problem is:

perimeter of the first rectangular board is 9 feet.

step-by-step explanation:

you divide the denominator by the numerator on both sides and if the quotients are equal then the fractions are equivalent