Evaluate the following expression when x=14. X^2+5x+11

277

Step-by-step explanation:

14^2+5(14)+11=

196+70+11=

277

Start by substituting 14 in for x everywhere that x appears in the problem.

So we have (14)² + 5(14) + 11.

Remember that PEMDAS tells you to deal

with your exponents before multiplying.

So you must square the 14 to get 196.

So we have 196 + 5(14) + 11.

Now multiply 5(14) to get 70.

So we have 196 + 70 + 11.

Now we can simply add to get 277.

answer is d-29

step-by-step explanation:

since you didn't include the picture, i can give you the description so you know how to pick the correct answer. the third quartile of a data is always shown in a box plot. in the middle of your graph should be a box. the third quartile is the value that goes with the far right edge of the box.