What are the solutions to x2+14x+40=0

x

2−14x+40=0 Factor x2−14x+40 using the AC method.(x−10)(x−4)

0 If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.x−10=0x−4=0 Set the first factor equal to 0 and solve.x=10Set the next factor equal to 0and solvex=4

The final solution is all the values that make (x−10)(x−4)=0 true x=10,4

Step-by-step explanation:IDK

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step-by-step explanation:

there would only be 50 odd numbers between 1 and 100 so therefor there would be 50 even so that would only be 50 odd numbers.