The height of an object off the ground, h (in feet) t seconds after it is launched into the air is given by h(t) = -16t2 + 640, osts 4.
Find the average rate of change of h over the interval [2, 4].
feet per second
Interpret your result.
During the last two seconds of the objects's time in the air, it is
feet per second.
---Select---
at an average rate of

hows it hangin lol

step-by-step explanation:

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18

-22

times both sides by 2, times () by 8, add alile terms, move terms, add alike and caculate divide both sides by 3

it would take 5 hours i think idk i'm not that good at math.can you me with my questions i need asap.