In a certain Algebra 2 class of 28 students, 9 of them play basketball and 17 of them play baseball. There are 6 students who play neither sport. What is the probability
that a student chosen randomly from the class plays both basketball and baseball?

Probability of a student playing both basketball and baseball is 4/28 or 14.3%

Step-by-step explanation:

1) Students playing atleast one sport = 28 - 6 = 22

2) N(Basketball ∩ Baseball) = N(Basketball) + N(Baseball) - N (Basketball U Baseball)

N(Basketball ∩ Baseball) = 9 + 17 - 22 = 4

3) Number of students playing both basketball and baseball = 4

Total number of students = 28

Probability of a student playing both basketball and baseball is 4/28

4/28= 0.1428571429 x 100%= 14.3%

its d but looking at that hurts my eyes frfr

step-by-step explanation:

, ; dcbsdkmnld

step-by-step explanation: