According to a company's website, the top 15% of the candidates who take the entrance test will be called for an interview. You have just been called for an interview. The reported mean and standard deviation of the test scores are 70 and 7, respectively. If test scores are normally distributed, what is the minimum score required for an interview?

The minimum score required for an interview is 77.252

Step-by-step explanation:

We solve this using z score formula

z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

Top 15% of the candidates is a ranking that is equivalent to = 100 - 15% = 85th percentile.

The z score of 85th percentile = 1.036

Mean = 70

Standard Deviation = 7

Minimum score = raw score = ???

Hence:

1.036 = x - 70/7

Cross Multiply

1.036 × 7 = x - 70

7.252 = x - 70

x = 70 + 7.252

x = 77.252

The minimum score required for an interview is 77.252