Prove cosec 2x + cot 2x = cot x

csc(2x) + cot(2x) = 1 / sin(2x) + cos(2x) / sin(2x)

csc(2x) + cot(2x) = (1 + cos(2x)) / sin(2x)

csc(2x) + cot(2x) = (1 + cos(2x)) / (2 sin(x) cos(x))

csc(2x) + cot(2x) = cos²(x) / (sin(x) cos(x))

csc(2x) + cot(2x) = cos(x) / sin(x)

csc(2x) + cot(2x) = cot(x)

step-by-step explanation:

b and c

the answer is b: 18

step-by-step explanation:

use the pythagorean theorem to .

a^2+b^2=c^2

plug 18 for "r"

the 2 legs are 18 and 24

18^2+24^2=c^2

324+576=c^2

900=c^2

c=30

30-12=18

18 is the radius

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