What is an equation in point-slope form of the line that passes through (-7, 1) and (-3, 9)?

y - y1 = m(x - x1)

m = Gradient

m = y - y1 / x - x1

Where:

(-7, 1) = (x, y)

(-3,  9) = (x1, y1)

m = (1 - 9) /( -7 + 3)

m = -8/- 4

m = 2

Inputing this into our point slope form equation : y - y1 = m(x - x1)

We have:

y - 9 = 2(x + 3)

Therefore, Option D is the correct option

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writing the linear equation can be used by any any of those coordinates that are given

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

the radius is 2 times the diameter.

step-by-step explanation: