BRAINLIEST Part A: Simeon comes home from school every day and eats 2 peanut butter and jelly sandwiches. There are 770 calories in 2 sandwiches. Set up the proportion to find how
many calories are in 1 peanut butter and jelly sandwich
Part B: Use the proportion set up in Part A to determine how many calories are in 1 peanut butter and jelly sandwich.
Part C: How many calories would be in 3 peanut butter and jelly sandwiches?

In one Pb&j it is 385 and in three it has 1,155 (385×3=1,155 )

part A = x= 385 Part B= Part A Part C= 1155

Step-by-step explanation:

Part A

770/2 = x/1

770= 2x

x= 385

Part B

Thats the same question as part A? so just use the answer from A i guess

Part C

770/2 = x/3

2310 = 2x

x = 1155

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

if you explain the the question more correctly i might be able to answer this better

step-by-step explanation: