Find two consecutive odd integers if twice the larger, increased by the smaller equals 37,

11 and 13

Step-by-step explanation:

the first (smaller) odd integer can be called x

the second (larger) odd integer can be called x+2

2(x+2)+x = 37

[simplify . . .]

2x+4+x = 37

3x+4 = 37

[subtract 4 from each side]

3x = 33

[divide each side by 3; find smaller odd integer]

x = 11

[add 2 to find larger odd integer]

x+2 = 13

a: 1/6, j: 1/4

step-by-step explanation: you are welcome