after how many seconds is needed for a thrown ball to reach a 14-m distance if it's distance is given by the relation d=10+40t-5t? (t=time in seconds)

The thrown ball will reach a 14-m distance after 0.114 seconds.

The relation given is:

d = 10+40t-5t

where, d = 14

In this case, we've to put the value of d into the relation and this will be:

d = 10+40t-5t

14 = 10 + 40t - 5t

Collect like terms

40t - 5t = 14 - 10

35t = 4

Divide both side by 35

35t/35 = 4/35

t = 0.114 seconds.

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Time, t = 0.1143 seconds.

Step-by-step explanation:

Given that distance, d = 14m

From the equation;

d = 10 + 40t - 5t

d = 10 + 35t

Substituting the value of distance;

14 = 10 + 35t

35t = 14 - 10

35t = 4

t = 4/35

t = 0.1143 seconds.

The time needed for the ball to reach the 14-m distance is 0.1143 seconds.

7. 153.86 ft

8. 12.56 ft

9. 78.5 m

10. 379.94 in

11. 132.665 m

12. 12.56 yd

13. 226.865 ft

14. 113.04 ft

15. 63.585 ft

16. 254.34 m

17. 50.24 cm

step-by-step explanation:

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answer:

c. the third graph